A student argues: *'Let . Then , so . Factorising, . Dividing by gives , so , hence .'* Which step is invalid?

Answer and explanation

Correct answer: C. Dividing both sides by

  1. Step 1: Since , we have .
  2. Step 2: Dividing both sides of an equation by is not allowed, so the step from to is invalid. All the other steps are valid algebra.
Answer
Dividing both sides by .
Why not the others: Multiplying by , subtracting , factorising a difference of squares, and substituting are all legitimate operations.

Practise more Errors in proofs.

Free questions with an explanation for every one, and full timed TMUA mock tests.