A student argues: *'Let . Then , so . Factorising, . Dividing by gives , so , hence .'* Which step is invalid?
Answer and explanation
Correct answer: C. Dividing both sides by
- Step 1: Since , we have .
- Step 2: Dividing both sides of an equation by is not allowed, so the step from to is invalid. All the other steps are valid algebra.
Answer
Dividing both sides by .
Why not the others: Multiplying by , subtracting , factorising a difference of squares, and substituting are all legitimate operations.
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