In a population in Hardy-Weinberg equilibrium, the frequency of a recessive allele (q) is 0.20. What percentage of the population is expected to be heterozygous carriers (2pq)?
Answer and explanation
Correct answer: D. 32%
- Step 1: Calculate allele frequencies: .
- Step 2: Compute heterozygous genotype frequency: .
Answer
32%.
Why not the others: 4% is the homozygous recessive frequency (); 64% is homozygous dominant (); 16% is without doubling.
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