In a population in Hardy-Weinberg equilibrium, the frequency of a recessive allele is . What percentage of the population is expected to be heterozygous ()?
Answer and explanation
Correct answer: B. 42%
- Step 1: Dominant allele frequency . Step 2. Heterozygote frequency (42%). Answer: Heterozygous frequency is 42%. Why not the others: or 42%.
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